Balancing a on neutral

[jeffhornsby]

I cannot locate my link for the formula but basically it i

(AxA+BxB+CxC)-(AxB+BxC+CxA) and take the square root of this number.

You use the formula Brian posted which is 10.6 if you change the values to 80 and 120
your formula will be about 6 amps off.
With 800 and 1200 you will be 58 amps off.
If the amps are not to high and your in field and do not have a calculator that formula will put you in ballpark