This is a 3 phase 480Vac heater circuit with only 2 heaters wired in a delta.
Consider a purely resistive heater circuit; 1 - 600W between phases 1 & 2 and 1 ? 900W between phases 2 & 3; for a total of 1500W.
Calculate the current in the common leg (2).
My approach was to use the following:
I = 1500 / 480 * 2 = 1.56Amps
Ic (common leg current) = I * 1.41 = 1.56 * 1.41 = 2.20Amps
Is this correct?
Consider a purely resistive heater circuit; 1 - 600W between phases 1 & 2 and 1 ? 900W between phases 2 & 3; for a total of 1500W.
Calculate the current in the common leg (2).
My approach was to use the following:
I = 1500 / 480 * 2 = 1.56Amps
Ic (common leg current) = I * 1.41 = 1.56 * 1.41 = 2.20Amps
Is this correct?