p051981
Member
- Location
- Houston, Texas
I need some help on wireway calculation. 376.22 (A) says wireways are limited to a maximum of 20% fill and 376.56 (A) says splices and taps must not fill more than 75% of the wiring space. So if I had:
3- 500 kcmil THHN = 2.1219 sq in
1- 250 kcmil THHN = .3970 sq in
4- 4/0 THHN = 1.2948 sq in
Total equals = 3.8137 sq in
Since 20% is equal to one-fifth
3.8137 sq in x 5 = 19.07 sq in
A 5x5 wireway would be sufficient.
Now my question is, how do you calculate for a 75% fill?
3- 500 kcmil THHN = 2.1219 sq in
1- 250 kcmil THHN = .3970 sq in
4- 4/0 THHN = 1.2948 sq in
Total equals = 3.8137 sq in
Since 20% is equal to one-fifth
3.8137 sq in x 5 = 19.07 sq in
A 5x5 wireway would be sufficient.
Now my question is, how do you calculate for a 75% fill?