The electromagnetic force exerted between two current-carrying conductors depend on: the current in the conductors, the shape and the arrangement of the conductors, natural frequencies of the complete assembly, mounting of structure, insulators, and conductors. (Std. Handbook for EE, CH17:17-27)
Formula:
F = M x (5.4 x I^2)/(S x 10^7);
where F = lbs of force per foot of conductor
M = a factor depending on the circuit type
I = short-circuit current
S = spacing, center-center of cond., in.
For 3-phase, maximum peak, choosing M = 0.8866 and a spacing of 6 inches, we have:
F = (0.866) x (5.4 x 1000^2)/(6 x 10^7) = 0.07794 lbs/foot of conductor
= 1.13 N per meter of conductor
(1 newton = 0.2248089 lbf and 1 meter = 3.28 feet)
P.S If it were DC current where the Table 17-7 say M = 1, @gar's computation result of 1.31 N/ meter of conductor is spot on!.