squaredan
Senior Member
- Location
- Pennsylvania
Hi,
This is my first post on this forum andI hope I am in the right section for this question.. I have been studying for my master and I came across a question in the Mike Holt Exam Prep Book and I am not understanding why would not use Table 310.15B2a for Adjustment in this question.. The Question is
" What size overcurrent protection device is required fro a 45A continuous load? the circuit is in a raceway with 14 current carrying conductors. (a) 45A (b) 50A (c) 60A (d) 70A "
The answer in the book is 60A
I understand we take 125% (210.20) of a continuous load 45A x 1.25= 56.25A and 240.4B lets us go to the next higher size 60A but then why wouldnt we take the Adjustment factor of table 310.15B2a of 14 current carrying conductors? I have been trying to find a code rule but not finding..Maybe it is wrong in the answer key??? Hope someone can help me on this one.. Thanks
Dan
This is my first post on this forum andI hope I am in the right section for this question.. I have been studying for my master and I came across a question in the Mike Holt Exam Prep Book and I am not understanding why would not use Table 310.15B2a for Adjustment in this question.. The Question is
" What size overcurrent protection device is required fro a 45A continuous load? the circuit is in a raceway with 14 current carrying conductors. (a) 45A (b) 50A (c) 60A (d) 70A "
The answer in the book is 60A
I understand we take 125% (210.20) of a continuous load 45A x 1.25= 56.25A and 240.4B lets us go to the next higher size 60A but then why wouldnt we take the Adjustment factor of table 310.15B2a of 14 current carrying conductors? I have been trying to find a code rule but not finding..Maybe it is wrong in the answer key??? Hope someone can help me on this one.. Thanks
Dan