You see somthing that I don't. I don't get the Cal. that you worked out. Please heip me on this one. How does
(480/120) give us 120A's? Or it that 480/120=4, then 4 x 30A's=120A's. Is this the part where they talk
of the turn's ratio? Don't seem to get the math.
Yes, 4 x 30 =120, that would be the minimum required ampacity of the secondary conductor to be protected by a 30A primary OCPD.
And yes it has to do with the turns ratio mentioned in 240.21(C)(1). Following the language in 240.21(C)(1), the secondary conductors can be permitted to be protected by the primary OCPD (
30A), provided this protection does not exceed the value determined by multiplying the secondary conductor ampacity by the secondary (120) to primary (480) turns ratio.
So if the secondary conductor was #2, with an ampacity of 115 Amps, the value determined by multiplying the secondary conductor ampacity by the secondary to primary turns ratio would be: 115 x (120/480) =
28.75. As you can see, the primary OCPD exceeds 28.75, so #2 would
not be permitted.
If the secondary conductor was #1, with an ampacity of 130 Amps, the value determined by multiplying the secondary conductor ampacity by the secondary to primary turns ratio would be: 130 x (120/480) =
32.5. Here, the primary OCPD does NOT exceed the value of 32.5, so #1 is permitted. So, #1 is the minimum required size.