Ivan Young
Member
- Location
- Simpsonville, South Carolina
Gentlemen, I am finally taking my Journeyman exam in July and have a few questions.
Lets you have the following circuits: 2) 20 amp 120v receptacle circuits, 2) 20 amp 120v lighting circuits, 1) 20 amp 120 v washer circuit, 1) 40 amp 240v dryer circuit. All circuits are going be piped from the panel to a JB 50 feet away. From the JB the various circuits will be piped to their final destinations. You have to figure the different wire sizes. By my count I have 13 current carrying wires, so I would have to derate by 50%. Since I already know the load and the correction factor I would take each 20 amp circuit and calculate: 20a/ .50=40a. So under the 60 degree column I would pick a #8 wire. For the 40a 240v circuit: 80a. I would pick a #3 wire.
Then based on the different wire sizes I would size my conduit.
How did I do?
Thanks,
Ivan
Lets you have the following circuits: 2) 20 amp 120v receptacle circuits, 2) 20 amp 120v lighting circuits, 1) 20 amp 120 v washer circuit, 1) 40 amp 240v dryer circuit. All circuits are going be piped from the panel to a JB 50 feet away. From the JB the various circuits will be piped to their final destinations. You have to figure the different wire sizes. By my count I have 13 current carrying wires, so I would have to derate by 50%. Since I already know the load and the correction factor I would take each 20 amp circuit and calculate: 20a/ .50=40a. So under the 60 degree column I would pick a #8 wire. For the 40a 240v circuit: 80a. I would pick a #3 wire.
Then based on the different wire sizes I would size my conduit.
How did I do?
Thanks,
Ivan