130804-1414 EDT
Some basic practical transformer theory.
For a closely coupled iron core transformer (low leakage flux), and only slightly saturating, the open circuit voltage ratio will be closely related to the turns ratio, and the same for the current ratio. The input current waveform will be very close to the output waveform.
Full load output current will reflect to the input very closely to the turns ratio. Full load output voltage will be substantially lower than predicted by the turns ratio because of the transformer internal impedance. Thus, in many transformers the actual turns ratio will be adjusted to a value that provides the desired output voltage at full load.
Consider an example:
Input voltage 240 to an output of 120 at full load. Suppose output drops 5% at full load. The theoretical turns ratio for no load is primary to secondary, 2 to 1. The current ratio will be 1 to 2.
Adjust the ratio to compensate for the 5% voltage drop. Thus, turns ratio becomes about 2 to 1.05 = 1.90 vs 2.00. Now the input current = output current / 1.90 or 0.525 times output current.
Turn the power flow around. The output voltage at full load is about Input voltage * 1.90 * 0.95 = 1.81 * Input voltage. Input current is about 1.9 * Output current.
If the same kind of meter is used to measure input and output current, then it does not matter whether it is RMS or full-wave rectified average reading. The waveform is the same at both the input and output.
There is something wrong with the information in the original post, or there is insufficient information, or additional needed measurements were not made.
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