Chris McCutcheon
Member
- Location
- Frankfort,KY
I have a test question that I'm having some difficulty answering. The question states: Calculate for the Over Current Protection Device. 25 HP, 3 phase, 208 volt. Design "B" with an Instantaneous Trip Breaker. OK... I understand that I need to go to 430.251(B) and I get a FLC of 404. What I'm confused about is what to do with the information from 430.52. If I multiply I get 4444 amps. Is this the setting on the breaker? If that's the case would the breaker be 600 amps. I have read 430.52 (3) Exceptions 1 and 2 but I must be missing something.