eddie_kerri
Member
- Location
- cincinnati, ohio
A long time ago, I can remember changing 4 foot T12 lamps out in a shoe store while the circuit was energized (stupid). The 2x4 fixtures were butted end to end and I remember how hard it was to remove one old lamp to install a new lamp. The process seemed to go as follows: I would rotate the lamp, pull one end of the lamp out of the tombstone while the other end was still in the tombstone. The cathodes on one end of the lamp would drag across the metal housing until I got the lamp low enough to remove the other end out of the tombstone. My question is: why didn't the circuit trip when one end of the lamp was touching the metal housing of the fixture and the other end still in the tombstone? My understanding is the output voltage of a ballast is very high and would seemingly trip the circuit very quickly based on this scenario. I don't know why I was thinking about this today at work, but it popped into my head so I thought I would present this question to the forum.