The calculation sequence (formula?) I use for 3 phase delta loads is to take the total KW and divide by line voltage and then divide that by the square root of three to get the line current.
I then have to divide by the square root of three to get the phase current.
I am confused by the first division by the square root of three. I'll look at it another way, starting at each load. Say the overall KW in my delta connected load is 30KW. The KW at each load will be 30/3= 10KW. I then take 10KW divide that by the line voltage (480V) and I get 20.83A. This would be the current through each load of the 3 phase delta. I multiply that by the square root of 3 and I get a line current of 36.08A.
Now is where I get confused. If I multiply it one more time by the square root of 3, I get 62.5A. This is the same amperage I get if I divide the entire load by 30000W by 480V = 62.5.
In summary, I understand the Line and Phase calculation but I do not understand why I have to divide 62.5A by the square root of three to get the line voltage, and then divide by the square root of three again to get the phase current. What is the initial 62.5A divided by the square root of three?
I then have to divide by the square root of three to get the phase current.
I am confused by the first division by the square root of three. I'll look at it another way, starting at each load. Say the overall KW in my delta connected load is 30KW. The KW at each load will be 30/3= 10KW. I then take 10KW divide that by the line voltage (480V) and I get 20.83A. This would be the current through each load of the 3 phase delta. I multiply that by the square root of 3 and I get a line current of 36.08A.
Now is where I get confused. If I multiply it one more time by the square root of 3, I get 62.5A. This is the same amperage I get if I divide the entire load by 30000W by 480V = 62.5.
In summary, I understand the Line and Phase calculation but I do not understand why I have to divide 62.5A by the square root of three to get the line voltage, and then divide by the square root of three again to get the phase current. What is the initial 62.5A divided by the square root of three?