Not true at all! If instead of pulling three hots and one neutral (total of 3 current-carrying conductors) you pull three hots and three neutrals, you wind up with three circuits, each being a 2-wire circuit, and you have to count all 6 wires as being current-carrying. In this case, 5(a) (2011 NEC) does not apply, because each of the three neutral wires will carry the same current as the hot wire with which it is associated, and not just an unbalanced current.
Originally Posted by Guyute
Charles E. Beck, P.E., Seattle
Comments based on 2008 NEC unless otherwise noted.