rolling offsets

[copper chopper]

is there a website you guys could give for formulas on figuring rolling offsets , now i am not talking about 3/4 pipe but doing this on 4 inch emt. making mistakes can be costly so I want to be able to figure it out and i cant measure it daignoly I have rise and how much over measurements. I cant seem to find a conduit bending section on this website there should be.

[buddhakii]

Just mark it out on the floor and wall with a pencil and measure.

[masterinbama]

Figure out what you need on a piece of 1/2" and transfer your results to your 4"

[WIMaster]

Figure out what you need on a piece of 1/2" and transfer your results to your 4"

+1 ! By far the easiest, least costly and most accurate method, especially for 4".

You could measure down an over then find the hypotenuse, but any mistakes in that method will cause a bad offset and require a calculator that does Sq. root. A piece of 1/2 emt can be tweaked to fit then either measure the offset or match it.

[masterinbama]

There is a way to do it with an old style wooden ruler but it can't be explained, it has to be visually demonstrated.

[ptonsparky]

There is a way to do it with an old style wooden ruler but it can't be explained, it has to be visually demonstrated.

Let us know when you post the video. I was never trained in the method, but managed in a crude fashion.

Folding ruler, test light kit with seriesed lamps, and for the geek I was, a slide rule. I gave them up in reverse order.

[George Stolz]

Just mark it out on the floor and wall with a pencil and measure.

That's the way I do it.

[tommy]

I think the formula for rolling offsets is A sq + B sq = C sq rt

For instance 8" offset but need to roll 3" to left or right

8X8= 64 3X3=9
64+9 = 73
73 sq rt =8.544"

[Strathead]

I think the formula for rolling offsets is A sq + B sq = C sq rt

For instance 8" offset but need to roll 3" to left or right

8X8= 64 3X3=9
64+9 = 73
73 sq rt =8.544"

I have never calculated a rolling offset, but my spidey sense confirms your formula. Simple enough, since the rise (8") and the side slip (3") are two sides of a traingle with a right angle between and the desired length is the hypotenuse, then Pythagorean's theorum is correct.

[velocityloop]

search online for iphone apps...Master Bender $3.99 willl do rolling offsets
android electrical wiring pro $2.99
etc