Originally Posted by

**Ingenieur**
I looked at it as a 480 ph-ph

this would involve 2 reactors (the 480 with be 1ph, but I guess you could use sqrt3)

this equates to a ph ang of 83 deg

what is the current rating?

S fault ~ 54.0400 Mva

1ph source Z ~ 480/(1.732 x 65000) = 4.2635 mOhm, 7.3846 3ph

1ph reactor Xl = 25.2584, 3ph 43.7488

total Z = 480/9415 = 50.9825 3ph, 1ph 29.4847

reactor Z = total - source = 43.5979 3ph

but reactor X > Z so R can't be calculated

it appears that rounding the ratings prevents calc R

but it looks like x/r >100 is a safe assumption

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