MarkShamp
Member
- Location
- Port Angeles Washington
I need to find the Formula for determining Fault Currant
The Inspector Wrote a corrections stating that we needed to "verify available fault currant from utility trans"
At the second lug there is 38,000amps
We used Mikeholtz formula but the inspector wants us to do the calculations long hand to further the amps down. So I was hoping that there was a Fault Currant Calculator somewhere that would tell us how to do it long hand...
MarkShamp
Ohm's Law: E = IR. You are suggesting dividing I by R. What is that intended to give, as a result?. . . the available fault current . . . divide by the transformer impedance. . .
Ohm's Law: E = IR. You are suggesting dividing I by R. What is that intended to give, as a result?
Impedance. It's an important distinctinction in determining fault current on AC systems.Simple: Ohm's Law. Current equals voltage divided by resistance.
Actually the transfomer impedence will be a %, so he is saying divide I by %, dont know what those units would be.