The impedance, Z, adds by the reciprocal of the sum of the reciprocals. Therefore given 10 conductors of equal length, and equal impedance, the impedance of the 10 conductors in parallel will be equivalent to 1/10th the impedance of a single conductor. Pretty straight forward math.

Now, if you vary the impedance of 1 set of conductors by increasing the length, then you have the reciprocals of 9 conductors of equal impedance added to the reciprocal of the other conductor, and invert.

Example:

Assume 100ft of (10) 500 KCMIL all same length-

Attachment 1014

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