So divide .804 by .22Okay, Look at Table 4 in chapter 9. Look at nominal diameter of ent
Found it. Fill does not apply 800.110(B), so this is a bad question.As far as I know, cat 6 cables do not have to meet the chapter 9 fill requirements. So, unless I am wrong, this should be clarified in the question.
Yes you did it wrong. where are you getting the 40% fill figure from or what is your basis for using that number?.22 is the diameter so the sq. in. would be (.11*.11) or .0121* 3.14 = .038
.038*4(cables) = 0.152 for a 40% fill.
1/2" would be too small so 3/4" would be it (if you were bound by the NEC tables).
If I did that wrong, someone will chime in.
Chapter 9 Table 1, 4 cables.Yes you did it wrong. where are you getting the 40% fill figure from or what is your basis for using that number?
Did not check your math, but you were the first to state that the .22 is cable diameter and that the calculations neccessary need to consider cross sectional area of what will be pulled in vs CSA of the raceway..22 is the diameter so the sq. in. would be (.11*.11) or .0121* 3.14 = .038
.038*4(cables) = 0.152 for a 40% fill.
1/2" would be too small so 3/4" would be it (if you were bound by the NEC tables).
If I did that wrong, someone will chime in.
Yes, question doesnt state each cable is .22 inches, so i looked at Table 1 and said 1 inch, but didnt convert to sq inch before looking at chart, so 40% rule apply or not after converting to sq inch?Chapter 9 Table 1, 4 cables.
I took this to mean that each cable was .22 inches in diameter. Typically you would give the diameter of each cable if it wasn't and you wouldn't add the diameter of each cable together and present that information.Yes, question doesnt state each cable is .22 inches, so i looked at Table 1 and said 1 inch, but didnt convert to sq inch before looking at chart, so 40% rule apply or not after converting to sq inch?
What trade size ENT raceway is required for four Cat 6 cables having a diameter of 0.22 inches?
Question you posted says each cable has a diameter of .22 inches.Yes, question doesnt state each cable is .22 inches, so i looked at Table 1 and said 1 inch, but didnt convert to sq inch before looking at chart, so 40% rule apply or not after converting to sq inch?
Thanks for the help, I was on right path just didnt convert to sq inch before looking at Table 1I took this to mean that each cable was .22 inches in diameter. Typically you would give the diameter of each cable if it wasn't and you wouldn't add the diameter of each cable together and present that information.
4 cables = 40% fill