I need assistance with determining my Watts correctly with Ohm's law using the amperage reading from my Fluke clamp meter. I welcome anyone who can correct the errors of my ways and offer a brief explanation so I can learn correctly.

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P(w) = V x I

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Any help with this would be greatly appreciated.

**Amperage Readings**L

^{1}: 17.1 AmpsL

^{2}: 17.0 Amps**Ohms Law**P(w) = V x I

__Calculated ohms law for each leg of the circuit, calculated them individually, then added the wattage together.__**Method 1:**L

^{1}: 17.1A x 120V = 2,052 WattsL

^{2}: 17.0A x 120V = 2,040 Watts__Total Watts__

^{1}: 4,092 Watts__Combined amperage for both legs and used 240V by combined average to calculate watts which is double Method 1.__**Method 2:**L

^{1}: 17.1 AmpsL

^{2}: 17.0 AmpsL

^{t }= 34.1 Amps x 240V = 8,184 Watts__Total Watts__

^{2}: 8,184 Watts

Any help with this would be greatly appreciated.

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