I'm working through Annex D Example D3(a) and need help understanding why the 3,960 VA of receptacle load is assumed to be equally distributed between all three phases when performing the conversion to amperes if we are dealing with 22 receptacles... If we assume near equal balancing, why wouldn't one phase have 180 VA more than the other two phases? and why isn't this reflected in the neutral load even if its fed from a SDS?

Secondly, why are they using 99,000 VA instead of 113,200 VA for determining the ungrounded feeder conductor size?

In the example, 195 amperes X 0.96 X 0.7 = 131 A does not have sufficient ampacity to carry 136A.

Wouldn't this require 3/0 instead of 2/0 since 225 amperes X 0.7 X 0.96 = 151 A and is greater than 136 A?

Thanks in advance.

Secondly, why are they using 99,000 VA instead of 113,200 VA for determining the ungrounded feeder conductor size?

In the example, 195 amperes X 0.96 X 0.7 = 131 A does not have sufficient ampacity to carry 136A.

Wouldn't this require 3/0 instead of 2/0 since 225 amperes X 0.7 X 0.96 = 151 A and is greater than 136 A?

Thanks in advance.

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