hitehm
Member
- Location
- Las Vegas NV
Hey All, I'm about to take the Journeyman exam. I'm using several study books that seem to be contradicting whether or not the demand factors in Art 220 for "load" calculations should be applied when determining a branch circuit ampacity, OC protection and the circuit conductor size.
Here is a question from Dewalt: " Given: A 240V single phase 17kW rated electric range is to be installed in the kitchen of a 1 family dwelling unit. Determine the minimum size copper NM cable the NEC requires to supply the electric range."
To me, the question is asking about conductor size so I immediately think to find the needed ampacity and whether or not the load is considered continuous and simply to ohm's law. In this case, not continuous and therefore, 17000w/240v = 70.83 amps which would give me a size 3 copper conductor under the 60deg C column for NM cable. Since no derating was needed I couldn't use the 90deg C column - 334.80. The author on the other hand applied the demand factor table 220.55 to the range wattage using column C row 1 for the single range. He added the 25% increase for the 5 kilowatts over 12kW and correctly came up with 10kW total. The problem is, I DON'T SEE WHY HE USED THIS AT ALL! This is NOT a load calculation, it's a cable size calc via the "ampacity rating" of the circuit. That range is capable of pulling 70.83 amps at full load. He sited note 4 from table 220.55 for reason for doing this. Is he correct? What am I missing? Please Help!!
Here is a question from Dewalt: " Given: A 240V single phase 17kW rated electric range is to be installed in the kitchen of a 1 family dwelling unit. Determine the minimum size copper NM cable the NEC requires to supply the electric range."
To me, the question is asking about conductor size so I immediately think to find the needed ampacity and whether or not the load is considered continuous and simply to ohm's law. In this case, not continuous and therefore, 17000w/240v = 70.83 amps which would give me a size 3 copper conductor under the 60deg C column for NM cable. Since no derating was needed I couldn't use the 90deg C column - 334.80. The author on the other hand applied the demand factor table 220.55 to the range wattage using column C row 1 for the single range. He added the 25% increase for the 5 kilowatts over 12kW and correctly came up with 10kW total. The problem is, I DON'T SEE WHY HE USED THIS AT ALL! This is NOT a load calculation, it's a cable size calc via the "ampacity rating" of the circuit. That range is capable of pulling 70.83 amps at full load. He sited note 4 from table 220.55 for reason for doing this. Is he correct? What am I missing? Please Help!!