jcole
Senior Member
- Location
- Lawrenceburg, Kentucky
Hello guys and gals
I have a 1500 KVA 480V transformer that feeds a 2500A rated main on a drawout switchgear.
I am wanting to figure out what size, in kw, generator I would need for standby power to replace the transfomer in case of failure, power loss, etc.
I know that to find kw the formula would be VA(1.732)PF. I also know I should size the generator for the loads but I would like to size it for the current available at the transformer. The primary of this transformer is fused at 150A at 12470V.
My calculation:
A=kva(1000)/V(1.732)
A=1500(1000)/480(1.732)
A=1804
Kw=VA(1.732)PF
Kw=480(1804)(1.732)(.9)
Kw=3560
How would you have went about finding this?
All comments apprecitated.
I have a 1500 KVA 480V transformer that feeds a 2500A rated main on a drawout switchgear.
I am wanting to figure out what size, in kw, generator I would need for standby power to replace the transfomer in case of failure, power loss, etc.
I know that to find kw the formula would be VA(1.732)PF. I also know I should size the generator for the loads but I would like to size it for the current available at the transformer. The primary of this transformer is fused at 150A at 12470V.
My calculation:
A=kva(1000)/V(1.732)
A=1500(1000)/480(1.732)
A=1804
Kw=VA(1.732)PF
Kw=480(1804)(1.732)(.9)
Kw=3560
How would you have went about finding this?
All comments apprecitated.