Well, it depends on your definition of "far". It also depends on "how much".
There are one or two enemies of long distance power transmission.
The first is resistance. Every real cable has resistance, and if you pass electricity through the cable, the resistance losses of the cable will convert some of that power to heat. The longer, or thinner the cable, and the more current (amps) it carries, the greater the losses, mathematically these are worked out as I*I*R, writting I2R, pronounces eye squared are.. So the losses go up lineraly by distance, and by the square of current. Thus you want to carry the minumum current possible, which means you use higher voltages and lower currents to carry the same power.
The second enemy is uniuqe to AC transmission and is capacitance. This is a loss that goes up linearly by the length of the cable, and if the cable is long enough then no power comes out the other end; it is all lost. The amount of capacitance depends on the cable and its installation method, but it is noteworthy that undersea cables are much worse than overhead cables. The limit on an AC undersea cable is about 30 miles from memory; after that all the power is lost.
The cure for this problem is DC transmission (HVDC) which can carry power thousands of miles with no capacitive losses. But you still get I2R losses.