jljones
Member
- Location
- Pennsylvania
In an 800 amp service which is fed with (2) 500 MCM parallel conductors per phase. How would I calculate my grounding electrode conductor?
One or two raceways?In an 800 amp service which is fed with (2) 500 MCM parallel conductors per phase.
This assignment is based on the 2008 code. and there is no mention of one or two raceways. So I will assume only one. I know its not good to assume.:grin:
Thanks for your reply and I have looked at 250.66. According to the table it should be 1/0 copper for 500 MCM, what I wasn't sure of if I had to add the two conductors together for a total 1000 MCM. In that case the grounding electrode would need to be a 2/0 AWG.
thank you for not just giving me the answer, I am a 52 year old laidoff construction project manager who came up through the field and worked my way up. I have done electric work for the past twenty five years, but I never had to figure any of this stuff out for myself.
Thanks again for your help.
Would you believe just making conversation? :roll:Thats OK, I can not for the life of me figure out why it would make a difference.
Hopefully Larry will explain.
This poster is not the one who started the thread...:grin: I took what you wrote as thinking he was the same guy. Forgive me if I misspoke.Originally you spoke of an 800 amp service with two parallel conductors per phase, but now you mention a 400 amp switch.
This poster is not the one who started the thread...:grin: I took what you wrote as thinking he was the same guy. Forgive me if I misspoke.![]()