I'm running a cable out to a double wide trailer to supply it power. The main breaker will be 200 Amps and is 780ft from the trailer. We will be using CLX cable. The voltage is 120/240V. I used Voltage Drop = (2 x K x I x Distance)/CM . With K = 12.9 ohms for copper, I = 200Amps, Distance = 780ft, and CM = 600,000 for 600 KCmil. So I got VD = 6.71; therefore 6.71V/240V x 100% = 2.8% voltage drop. The biggest wire the wiring company we go with offers is 750 KCmil. Since it is 120/240V it's single conductor? I'm not to sure on this since I haven't had any experience sizing wires or using the NEC since I just graduated college.
Not to sure on how the parallelling wires works either. For this case if I had 3 - 4/0 AWG single conductors in parallel running out there would it work and would it be cheaper than a 750 KCmil? The code says 1-3 and you don't have to adjust the value. So my allowable amps for my breaker would be 3 x 260A = 780A for my breaker using table 310.16, 90C, Copper, XHHW-2. Which seems high but the Voltage Drop calculation would be = (2 x 12.9 ohms x 200A/3 x 780ft)/211600 = 6.34 Volts. Then 6.34V/240V x 100% = 2.64% VD. Is any of this correct or am I way off?
Not to sure on how the parallelling wires works either. For this case if I had 3 - 4/0 AWG single conductors in parallel running out there would it work and would it be cheaper than a 750 KCmil? The code says 1-3 and you don't have to adjust the value. So my allowable amps for my breaker would be 3 x 260A = 780A for my breaker using table 310.16, 90C, Copper, XHHW-2. Which seems high but the Voltage Drop calculation would be = (2 x 12.9 ohms x 200A/3 x 780ft)/211600 = 6.34 Volts. Then 6.34V/240V x 100% = 2.64% VD. Is any of this correct or am I way off?