I'm studying to take my journeymans test and after going through mikes dvd on motor and air conditioning calculations I found out that I can put a #14 awg wire on a 30 amp breaker thats providing short circuit and ground fault protection, ( I included the motor I used below) because of 240.4 (D) which points me to Table 240.4 (G) which states I go to Article 430 Parts III, IV, V, VI, and VII for specific conductor applications instead of following the rules contained in 240.4 (D) which would have other wise made me go from #14 awg to #10 awg for a 30 ampere breaker. Well in school I brought this up to my instructor and he said no your wrong you cant do that, and you must use #10 awg wire and he pointed to article 240.4 (D) and said basically article 430 points you back to 240.4 (D) to apply that article. I'm not seeing it. I still think I'm right! I dont know why this is bugging me so much but I dont want to go in and take my journeymans test and fail by one percentage point because of this. If I'm right can someone please explain to me an easy way to explain this to him.
here was my motor example:
2HP Motor motor terminals 75 degree c terminals
230V
11A FLA
12FLC
Conductor size: 12x125%= 15A .....so I used 14awg wire rated at 20A
Breaker: 12 FLC x 250%= 30A Breaker
here was my motor example:
2HP Motor motor terminals 75 degree c terminals
230V
11A FLA
12FLC
Conductor size: 12x125%= 15A .....so I used 14awg wire rated at 20A
Breaker: 12 FLC x 250%= 30A Breaker