open delta

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welch

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if the secondary windings of 2 single-phase transformers are connected in the open delta pattern. If the windings each produce 600 volts acrosss there windings, what would be the "open" voltage
 
Welch, welcome to the forum! :)

welch said:
if the secondary windings of 2 single-phase transformers are connected in the open delta pattern. If the windings each produce 600 volts acrosss there windings, what would be the "open" voltage
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I could give the standard "What do you think it would be, and why?" but I won't.

Presuming that the primary voltages are correct (which we should be able to do), it would also be 600v, just like it would be with a full Delta.

Otherwise, an unloaded Delta would have high secondary currents. Imagine making a full Delta with one wrong secondary voltage.
 
Open Delta

Open Delta

Depends on what the phase connections are.

Assume a three phase supply and that the transformers are connected A-B and B-C on the primary. One transformer's output is in phase with A-B and the other is in phase with B-C. The open end terminals have a voltage in phase with C-A, so it is 600V. (That's the normal open delta connection.)

If one transformer had reversed polarity the output would be 600V x 1.732= 1040V.

If we had a single phase input on the primary, we could get 0 or 1200 volts, depending on the polarity of the transformer connections.

Connect one A-N and one B-N on the primary (assuming 4-wire system) and the open voltage will be 600V x 1.732 = 1040 V (or 600V if the polarity is backwards).

But I think the short answer you wanted is 600V.
 
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