brother
Senior Member
I want to make sure Im doing this right in my calculation, there are 2 cables , each cable has 19 pairs. The o.d. on one cable is .603 inches. this is NOT square inches so I had to convert. I came up with using 1 1/2" emt conduit NEC 2008 TABLE 4 chapter nine.
Area= 3.14 * R(squared)
R= D/2
D= .603
R= .603/2=0.3015
Area= 3.14 X .3015 X.3015=.285
2X .285=.570 1 1/2 EMT conduit size needed. (0.631 sqr inches for emt)
since there are 2 cables and that means I have 2 conductors and have to use the 2 wires 31% fill.
Did I do this right?? I dont deal with multi cables much, just regular wire!
Area= 3.14 * R(squared)
R= D/2
D= .603
R= .603/2=0.3015
Area= 3.14 X .3015 X.3015=.285
2X .285=.570 1 1/2 EMT conduit size needed. (0.631 sqr inches for emt)
since there are 2 cables and that means I have 2 conductors and have to use the 2 wires 31% fill.
Did I do this right?? I dont deal with multi cables much, just regular wire!