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kevinsryan

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For the following what is the calculated load. Is this the proper answer?
1- Range @ 11 kw
1- Cooktop @ 10 kw

11 & 10 = 21 kw
21/2 = 10.5 round up to 11
column C of 220.55 = 1 unit = 8 kw
 
kevinsryan said:
For the following what is the calculated load. Is this the proper answer?
1- Range @ 11 kw
1- Cooktop @ 10 kw

11 & 10 = 21 kw
21/2 = 10.5 round up to 11
column C of 220.55 = 1 unit = 8 kw
Click to expand...

My quess is you are using T. 220.55 for residential.

Note 2 states you must use 12kw for any unit rated under 12. Thus you would have 12 + 12 = 24/2 = 12.

Now you must increase the 8kw gotten from Col. C for one range by 5% for KW over 8kw. 12-8 =4. 5%* 4= 20%
8kw * 20% = 1.6

Thus you have 8kw + 1.6 kw = total load of 9.6 KW
 
Dennis Alwon said:
My quess is you are using T. 220.55 for residential.

Note 2 states you must use 12kw for any unit rated under 12. Thus you would have 12 + 12 = 24/2 = 12.

Now you must increase the 8kw gotten from Col. C for one range by 5% for KW over 8kw. 12-8 =4. 5%* 4= 20%
8kw * 20% = 1.6

Thus you have 8kw + 1.6 kw = total load of 9.6 KW
Click to expand...

Dennis, not my strong point, but since we don't use Note 3, we use Column C. We fall under Note 2 and use 12kw for each for an average of 12. The average does not exceed 12 so there is no 5% multiplier.
Column C, 2 units = 11 kw
 
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