calculation for range

[kendrichchan]

a 16.75kw rated range have full current value of _______ amps for load calculation purpose? please show how
thanks

 

[Little Bill]

a 16.75kw rated range have full current value of _______ amps for load calculation purpose? please show how
thanks

Look at Table 220.55 and read note #1 and see if you can figure it out. If you can't, post how you tried and the problem you are having and one of us can help you from there.

 

[kendrichchan]

Look at Table 220.55 and read note #1 and see if you can figure it out. If you can't, post how you tried and the problem you are having and one of us can help you from there.

1 range 16.75= 12+(4.75x.05)=12,2375
12375/240=51.56amps
not sure I use the correct number.

 

[CONDUIT]

You increase the number in column "C" 5% for every KW or major fraction (.5 or higher) that your appliance exceeds 12 kw. You just have one appliance.

 

[Little Bill]

1 range 16.75= 12+(4.75x.05)=12,2375
12375/240=51.56amps
not sure I use the correct number.

Almost right. The 16.75 is a "major fraction thereof" so use 17k. You use the demand in column C which is 8k. You use the amount over 12k to get the demand multiplied by 5%.
17k-12k=5k 5 x.05=.25 8k+(8kx.25)=10k 10000/240=41.66A

 

[Dennis Alwon]

Almost right. The 16.75 is a "major fraction thereof" so use 17k. You use the demand in column C which is 8k. You use the amount over 12k to get the demand multiplied by 5%.
17k-12k=5k 5 x.05=.25 8k+(8kx.25)=10k 10000/240=41.66A

I agree with this.. assuming it is a residential range.