calculation for range

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kendrichchan said:
a 16.75kw rated range have full current value of _______ amps for load calculation purpose? please show how
thanks
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Look at Table 220.55 and read note #1 and see if you can figure it out. If you can't, post how you tried and the problem you are having and one of us can help you from there.
 
Little Bill said:
Look at Table 220.55 and read note #1 and see if you can figure it out. If you can't, post how you tried and the problem you are having and one of us can help you from there.
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1 range 16.75= 12+(4.75x.05)=12,2375
12375/240=51.56amps
not sure I use the correct number.
 
You increase the number in column "C" 5% for every KW or major fraction (.5 or higher) that your appliance exceeds 12 kw. You just have one appliance.
 
kendrichchan said:
1 range 16.75= 12+(4.75x.05)=12,2375
12375/240=51.56amps
not sure I use the correct number.
Click to expand...

Almost right. The 16.75 is a "major fraction thereof" so use 17k. You use the demand in column C which is 8k. You use the amount over 12k to get the demand multiplied by 5%.
17k-12k=5k 5 x.05=.25 8k+(8kx.25)=10k 10000/240=41.66A
 
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Little Bill said:
Almost right. The 16.75 is a "major fraction thereof" so use 17k. You use the demand in column C which is 8k. You use the amount over 12k to get the demand multiplied by 5%.
17k-12k=5k 5 x.05=.25 8k+(8kx.25)=10k 10000/240=41.66A
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I agree with this.. assuming it is a residential range.
 
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