kwired
Electron manager
- Location
- NE Nebraska
I forot to put in the 1.732 for three phase, which I believe was probably meant in the original question. That changes to 2106, not 1216.
Ok after a little reasearch, been trying to use wrong formulas I come up with same answer as Besoeker in posts 5 and 14.
here is formula:
P = V x A x PF (x 1.73 for three phase)
everything is known except for PF so we need to solve for PF
1576w = 240v x 5.892a x 1.73 x PF
can be re written as
1576w = 2446 x PF
divide both sides by 2446
.64 = PF
The motor has to be three phase otherwise the power factor will come out above 1.0.
Unfortunately .64 was apparently not one of the possible answers where this question came from
Efficiency is not needed to find the answer to this problem.
We should be able to find (output) horsepower by using efficiency in a similar formula to what we were trying to use before.
HP = V X A X eff x pf (x 1.73 for three phase) / 746 watts per horsepower
HP = 240 x 5.892 x .86 x .64 / 746
HP = about 1 hp. (this would be output power at shaft)