mivey
Senior Member
A brief note on the correct relationship between conjugating phasors and inverting phasors.
There are three common ways we use "conjugate" in relation to algebraic expressions, phasors, or angles:
1) Changing the sign of the second half of an algebraic expression
2) Changing the sign of the imaginary part of a complex expression (or changing the sign of the phasor's angle). This would be the most common use in a discussion on electric system phasors.
3) Conjugate angles are two angles that sum to 360?
In another thread, there were some incorrect uses of "conjugate" and "conjugation". The incorrect uses were:
1) Calling the conjugate of a phasor the same as the inverse of a phasor.
2) Calling the conjugate of an angle the same as the inverse of a phasor angle.
3) Saying that conjugating an angle is the same as inverting an angle.
Notes on error #1:
When we speak of inverting a phasor, we do so by taking the negative of the phasor, or by taking the negative of the complex number representation, or by shifting the phasor angle by 180?. When we conjugate a phasor, we do so by changing the sign of the phasor's angle, or by changing the sign of the imaginary portion of its complex number representation. So, taking the conjugate of a phasor and inverting a phasor are not the same. For example:
Invert{C@Θ?} = -1 * C@Θ? = C@(Θ? ? 180?)
Invert{A + jB} = -1 * (A + jB) = -A - jB
Conjugate{C@Θ?} = C@(-1 * Θ?) = C@(-Θ?)
Conjugate{A + jB} = A + j(-1 * B) = A - jB
Notes on error #2:
When inverting a phasor, we can do so by taking the negative of the phasor, or by shifting the phasor angle by 180?. If by calling the conjugate of an angle the angle found when we find the missing angle of a conjugate pair, we subtract the known angle from 360?. So, the conjugate angle is not the same as the inverse phasor angle. For example:
Invert{C@Θ?} = -1 * C@Θ? = C@(Θ? ? 180?)
Conjugate pairing angle{Θ?} = (360? - Θ?) => C@(360? - Θ?)
Notes on error #3:
Inverting the angle was referring to the angle change when inverting the phasor, or changing to the opposite direction. Not so sure what was meant by conjugating the angle as it is not common terminology. If conjugating an angle means finding the conjugate pair, see note on error#2. If conjugating an angle means the angle from conjugating a phasor, see note on error #1.
There are three common ways we use "conjugate" in relation to algebraic expressions, phasors, or angles:
1) Changing the sign of the second half of an algebraic expression
2) Changing the sign of the imaginary part of a complex expression (or changing the sign of the phasor's angle). This would be the most common use in a discussion on electric system phasors.
3) Conjugate angles are two angles that sum to 360?
In another thread, there were some incorrect uses of "conjugate" and "conjugation". The incorrect uses were:
1) Calling the conjugate of a phasor the same as the inverse of a phasor.
2) Calling the conjugate of an angle the same as the inverse of a phasor angle.
3) Saying that conjugating an angle is the same as inverting an angle.
Notes on error #1:
When we speak of inverting a phasor, we do so by taking the negative of the phasor, or by taking the negative of the complex number representation, or by shifting the phasor angle by 180?. When we conjugate a phasor, we do so by changing the sign of the phasor's angle, or by changing the sign of the imaginary portion of its complex number representation. So, taking the conjugate of a phasor and inverting a phasor are not the same. For example:
Invert{C@Θ?} = -1 * C@Θ? = C@(Θ? ? 180?)
Invert{A + jB} = -1 * (A + jB) = -A - jB
Conjugate{C@Θ?} = C@(-1 * Θ?) = C@(-Θ?)
Conjugate{A + jB} = A + j(-1 * B) = A - jB
Notes on error #2:
When inverting a phasor, we can do so by taking the negative of the phasor, or by shifting the phasor angle by 180?. If by calling the conjugate of an angle the angle found when we find the missing angle of a conjugate pair, we subtract the known angle from 360?. So, the conjugate angle is not the same as the inverse phasor angle. For example:
Invert{C@Θ?} = -1 * C@Θ? = C@(Θ? ? 180?)
Conjugate pairing angle{Θ?} = (360? - Θ?) => C@(360? - Θ?)
Notes on error #3:
Inverting the angle was referring to the angle change when inverting the phasor, or changing to the opposite direction. Not so sure what was meant by conjugating the angle as it is not common terminology. If conjugating an angle means finding the conjugate pair, see note on error#2. If conjugating an angle means the angle from conjugating a phasor, see note on error #1.