Wire Derating Question for 8 circuits.
I have 8 circuits going to heat trace.
I have three 30A cb for 3 circuits and five 20A cb for 5 circuits.
They are 120V circuits.
This is a total of 16 current carrying conductors
From my calculations I think I need Use #8 wire for the 30A
circuit breaker circuits and #10 wire for the 20 amp circuit
breaker circuits.
From Table Derating Table_310.15(B)(3)(a) I get a derating
factor of 50% for 16 current carrying conductors.
From table 310.15(B)(16) I get 30A, 90deg THHN for # 12 wire.
From table 310.15(B)(16) I get 40A, 90deg THHN for # 10 wire.
Ok,
For Number #12 wire to 20A CB I take (.8 * 20) to get 16A
From the Tables above (.5 * 30) is 15A
Since 16A > 15A so # 10 (one size bigger) is required.
For Number #10 wire to 30A CB I take (.8 * 30) to get 24A
From the Tables above (.5 * 40) is 20A
Since 24A > 20A so # 8 (one size bigger) is required.
Is this correct?
If not where is my error.
Thank you,
I have 8 circuits going to heat trace.
I have three 30A cb for 3 circuits and five 20A cb for 5 circuits.
They are 120V circuits.
This is a total of 16 current carrying conductors
From my calculations I think I need Use #8 wire for the 30A
circuit breaker circuits and #10 wire for the 20 amp circuit
breaker circuits.
From Table Derating Table_310.15(B)(3)(a) I get a derating
factor of 50% for 16 current carrying conductors.
From table 310.15(B)(16) I get 30A, 90deg THHN for # 12 wire.
From table 310.15(B)(16) I get 40A, 90deg THHN for # 10 wire.
Ok,
For Number #12 wire to 20A CB I take (.8 * 20) to get 16A
From the Tables above (.5 * 30) is 15A
Since 16A > 15A so # 10 (one size bigger) is required.
For Number #10 wire to 30A CB I take (.8 * 30) to get 24A
From the Tables above (.5 * 40) is 20A
Since 24A > 20A so # 8 (one size bigger) is required.
Is this correct?
If not where is my error.
Thank you,