We'll never be able to solve world piece at this rate :lol:
You all do realize you scared the OP'er off, :thumbsdown:
How many amps - 608A
Voltage - 480V, 3 phase
Step 1 - Pick minimum conductor size based on ampacity
608 x 1.25 = 760A, OK, you need 760A worth of cable.
Step 2 - Adjust for 2 sets per conduit, therefore 80% adjustment, i.e. 4 sets total
760A/2 x 1.25 = 475A worth of cable in each conduit
Step 3 - Go to Table 310.15 and select parallel conductors that add up to 475A or more
250KCMIL x 2 = 510A @ 30 deg C (minimum allowable conductor)
Step 4 - Do VD calculation to determine if a larger conductor is required
since a distance is unknown, will calculate the maximum distance you can go with a 250KCMIL loaded with 608A, 75 deg C, assuming max. of 3% VD, using steel conduit.
Dmax = approx 310ft, a longer run will require an increase in conductor size.