gar
Senior Member
- Location
- Ann Arbor, Michigan
- Occupation
- EE
160321-2004 EDT
michalspike:
No way are you going to make a simple current measurement in a residential application and determine energy usage for a month or year time period. An instantaneous current measurement with some additional information can give you an instantaneous power measurement, but that is not energy.
To determine energy used over some time period means you need to integrate the instantaneous power over that time with respect to time. That is what the power company electric meter does.
Instantaneous power is not the same as short time average power, but knowing short time average power and adding contiguous elements of short time average power times the averaging time over some long time period will give you the energy over that long time.
How to estimate the correctness of the power company meter? If the meter is electronic, then it is probably more accurate than instruments that you may have unless there is a gross error.
Find out how to use the power company meter to make short time energy measurements. Get information from the meter face and ask meternerd how to use that information.
You have two good resistive loads (the water heaters) to provide a known load. Turn off everything in the apartment except the water heaters. Drain enough hot water to force the water heaters to be full on for the time of your test. It is possible that the test time does not need to be more than a few to 10 minutes. This will be a function of how easy it is to read short time energy from the power company meter, and use of a stopwatch.
The water heaters are most likely 208 or 240 V units. Assume no major current from motors or controls goes to neutral. This means one or two ammeters and one voltmeter are your test instruments. Measure the current to each water heater, add the two currents, measure the line-to-line voltage, and multiply the summed current by the voltage to get average power. It is also necessary to measure and verify that this short time average power is constant during the test.
Assuming that the water heaters have stablized in power consumption, then multiply this average power by the time duration during which you read the power company meter. This time has to be in hours. So a 6.4 minute time period is 0.1067 hours. Compare this kWH estimate with the measured kWH from the power company meter.
.
michalspike:
No way are you going to make a simple current measurement in a residential application and determine energy usage for a month or year time period. An instantaneous current measurement with some additional information can give you an instantaneous power measurement, but that is not energy.
To determine energy used over some time period means you need to integrate the instantaneous power over that time with respect to time. That is what the power company electric meter does.
Instantaneous power is not the same as short time average power, but knowing short time average power and adding contiguous elements of short time average power times the averaging time over some long time period will give you the energy over that long time.
How to estimate the correctness of the power company meter? If the meter is electronic, then it is probably more accurate than instruments that you may have unless there is a gross error.
Find out how to use the power company meter to make short time energy measurements. Get information from the meter face and ask meternerd how to use that information.
You have two good resistive loads (the water heaters) to provide a known load. Turn off everything in the apartment except the water heaters. Drain enough hot water to force the water heaters to be full on for the time of your test. It is possible that the test time does not need to be more than a few to 10 minutes. This will be a function of how easy it is to read short time energy from the power company meter, and use of a stopwatch.
The water heaters are most likely 208 or 240 V units. Assume no major current from motors or controls goes to neutral. This means one or two ammeters and one voltmeter are your test instruments. Measure the current to each water heater, add the two currents, measure the line-to-line voltage, and multiply the summed current by the voltage to get average power. It is also necessary to measure and verify that this short time average power is constant during the test.
Assuming that the water heaters have stablized in power consumption, then multiply this average power by the time duration during which you read the power company meter. This time has to be in hours. So a 6.4 minute time period is 0.1067 hours. Compare this kWH estimate with the measured kWH from the power company meter.
.
Last edited: