Case 1: the 480 delta generator supplies a 480V:120/240V single phase transformer on 480V phases A-B. If the currents on the 120/240V side are I1 and I2 (neutral current is I1-I2), then the 480V primary current is (I1+I2)/4. If the generator windings are equal impedance, then the generator sees (I1+I2)/6 current on its A-B winding, and (I1+I2)/12 current on both the B-C and C-A windings.
Case 2: the 480 delta generator supplies (3) 480V : 120V single phase transformers in a low zig-zag. Say the current I1 is on the leg provided by one transformer on A-B, and the current I2 is provided by the zig-zag on B-C and C-A. The current on the generator A-B coil is I1 / 4, while the current on the B-C and C-A coils are both I2/4.
So if the 120/240 load is balanced of current I = I1 = I2, in case 1 we have I/3 on one coil and I/6 on the other two, while in case 2 we have I/4 on each coil.
Cheers, Wayne