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Thread: Buck and Boost

  1. #21
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    Gentlepeople...

    I apologize for the long delay, but my car was broad-sided in a CVS parking-lot, by a driver who lost control while responding to his cell-phone! However, it proved that more than 90% of car accidents happen within a few miles from home!

    Here is the correct solution using my Gi.Fi.E.S. method (pronounced Jiffy’s), where:
    o Gi means Given
    o Fi Find
    o EEquation
    o S Solution


    System Diagram








    Given:
    o IN and LD subscripts represent Source and Load parameters, respectively!
    o Source In: Volts, Amps, Apparent-Power = EIN (208V), IIN ( ? A), VAIN, respectively!
    o Load Data: Volts, Amps, Apparent-Power = VLD (240V), ILD (17A), VALD, respectively!
    o AT Configuration: Step-Up! Assume ideal, i.e., zero losses and leakage-impedance V-Drops!
    o AT Series-Winding: Volts, Amps, Apparent Pwr, = VSW ( 32V), ISW (?A), VASW), respectively!
    o AT Common-Wndg: Volts, Amps, Apparent Pwr, = VCW (208V), ICW (?A), VACW), respectively!

    Find:
    a) VAAT: Apparent-Power, by transformer-action, delivered to a 240V, 17A resistive load, from a 208V source!
    b) VACA: Apparent-Power, by conduction-action, to the same load!

    Equations: Solution:
    1) VALD = VLD x ILD 1) 4,080 VA
    2) VAIN = VALD 2) 4,080 VA
    3) IIN = VAIN / EIN 3) 19.62 Amps
    4) ISW = ILD 4) 17.00 Amps
    5) ICW = IIN – ISW 5) 2.62 Amps
    a) VAAT = (VLD – VIN) x ILD (Gar Short-cut) a) 544 VA
    b) VACA= VAIN x ILD b) 3,536 VA

    Additional comment:
    I’ve been asked a few times, “Why do I use the “Jiffy’s Method” when the “Shortcut” is simpler! I learned why in my second-career job working for a contractor involved in State and Federal Public-Works projects! I realized that countless hours were wasted arguing, quibbling, quarreling, and many times confronted by ‘King-of-the Hill” associates and yes, even bosses! Even witnessed a punch-up, once! The “Jiffy’s Method” cut out all of the above!

    Regards, Phil Corso

  2. #22
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    Ignore previous post!

    Gentlepeople…

    I apologize for the long delay, but my car was broad-sided in a CVS parking-lot, by a driver who lost control while responding to his cell-phone! However, it proved that more than 90% of car accidents happen within a few miles from home!

    Here is the correct solution using my Gi.Fi.E.S. method (pronounced Jiffy’s), where:
    o Gi means Given
    o Fi Find
    o EEquation
    o S Solution


    System Diagram









    Given:
    o IN and LD subscripts represent Source and Load parameters, respectively!
    o Source In: Volts, Amps, Apparent-Power = EIN (208V), IIN ( ? A), VAIN, respectively!
    o Load Data: Volts, Amps, Apparent-Power = VLD (240V), ILD (17A), VALD, respectively!
    o AT Configuration: Step-Up! Assume ideal, i.e., zero losses and leakage-impedance V-Drops!
    o AT Series-Winding: Volts, Amps, Apparent Pwr, = VSW ( 32V), ISW (?A), VASW), respectively!
    o AT Common-Wndg: Volts, Amps, Apparent Pwr, = VCW (208V), ICW (?A), VACW), respectively!

    Find:
    a) VAAT: Apparent-Power, by transformer-action, delivered to a 240V, 17A resistive load, from a 208V source!
    b) VACA: Apparent-Power, by conduction-action, to the same load!

    Equations:
    1) VALD = VLD x ILD
    2) VAIN = VALD
    3) IIN = VAIN / EIN
    4) ISW = ILD
    5) ICW = IIN – ISW
    a) VAAT = (VLD – VIN) x ILD (Gar Shortcut)
    b) VACA = VAIN x ILD

    Solution:
    1) 4,080 VA
    2) 4,080 VA
    3) 19.62 Amps
    4) 17.00 Amps
    5) 2.62 Amps
    a) 544 VA
    b) 3,536 VA

    Regards, Phil

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