Originally Posted by

**BatmanisWatching1987**
Thanks this will help me out a lot.

Correct me if I'm wrong,

For a Balanced 3 Phase Delta System, since Line Voltage and Phase Voltage are equal, and if the the impedance is given, we can use the phase current for theta to find the Total Power for 3 Phase Load, which was equal to 2.448 kW.

But, if we want to find the Single Phase Power we will use the line current angle, the power would be 0W? (Since the angle is 90 degrees)

I am not sure if I understand your question. Again, theta is you impedance angle; in this case (Zp=25<60 Ω) θ is 60 degrees. Where did you get 90 degrees? Load power always equals 3*|Iф|*|Vф|*cos(θ) where θ is the load impedance angle. Doesn't matter three phase Y, Δ or single phase. For single phase just remove the 3.

"Because it's there!"

George Mallory

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