I'm just a little confused by how to add the Voltage and Current for finding the Apparent Power Angle.
I understand we need to take the conjugate of the Current Angle.
So, without doing the conjugate of the Current Angle, would we add up the Voltage and Current Angle to get the Apparent Power to be <2.06+(-46.75), then we take the conjugate of the Current Angle to get <2.06+(+46.75).
Attachment 22390
Look at your attachment above (from post#18). The angle of current phasor, as worked out, is <-46.75 degrees.
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