I'm sticking with my original response, and adding that I believe that a single conductor (in this case, a cable of equal diameter) requires a larger conduit than three individual conductors.
I don't know anything about MV cable, but it's easy to do the comparison with Aluminum SER cable.
On the large side of things, 4/0-4/0-4/0-2/0 SER from Southwire has an OD of 1.496". If we use Chapter 9 Table 5A, 4/0 XHHW compact Al has a diameter of 0.590", and 2/0 has a diameter of 0.490" (we could use a bare 2/0 at 0.376", but I think that would be unusual).
So for minimum conduit internal area, we need to compare 1.496
2/0.53 = 4.22 to (3 * 0.59
2 + 0.49
2)/0.4 = 3.21 The single cable is worse, by a factor of 1.3. [The above aren't areas, but if you multiply them by pi/4, they are the minimum conduit areas in each case.]
Just to check the smaller side of things, 6-6-6-6 Al SER has an OD of 0.717", and #6 XHHW compact Al has a diameter of 0.260". Now we are comparing 0.717
2/0.53 = 0.97 to 4 * 0.26
2/0.4 = 0.68. Here the single cable is worse by a factor of 1.4.
For a simple approximation of a 3 conductor cable, the diameter of a circle enclosing 3 packed circles is approximately 2.154 times the packed diameter. So the comparison is 2.154
2/0.53 = 8.75 vs 3/0.4 = 7.5. For a ratio of 1.17; the actual case is worse as the cable has an outer sheath.
en.wikipedia.org
Cheers, Wayne