arc_flashed
Member
- Location
- FL, United States
I am looking for some clarification on how the VA for a single phase motor is calculated and how that translates into the loading/current flow on my wires when I'm adding it to a 3-phase distribution.
I have a single phase (L-L, no neutral) 208vac, 2HP motor. NEC FLA = 13.2 amps.
This works out to 208v * 13.2a = 2746VA.
My question is how does this 2746VA add to the load on the three phase conductors I have on a 208vac 3-phase breaker?
The total loading on this panel is 6amps at 120vac L-N plus the 13.2 amps 208vac L-L. If I do the math:
6A @120v = 720VA (phase A)
13.2@208v = 2746VA (phase B and C)
25% motor = 687VA
Total panel VA = 4153VA
If I convert this 4153VA to 208VAC 3PH:
4153VA/208v/1.73 =11.54amps
This seems incorrect as it would indicate that a 15amp 3P 208v breaker would be sufficient based on the calculated FLA of the panel. However, looking at my loads I would need a 20amp breaker for my motor load which is higher than the main. In my calculation above do I need to account for 2X the VA of the single phase motor since the 13.2amp will be flowing out one leg and back on the other without a neutral to sum at the main breaker?
I am attempting to minimize the load/feed on this panel as it is almost 1000ft away from the source so every amp really matters with the voltage drop. That is why we are looking at a 3phase distribution but running the numbers they don't seem to be adding up.
I was also using the 3-phase load calculation for the voltage drop which I am now questioning also.
Thanks in advance for any help.
I have a single phase (L-L, no neutral) 208vac, 2HP motor. NEC FLA = 13.2 amps.
This works out to 208v * 13.2a = 2746VA.
My question is how does this 2746VA add to the load on the three phase conductors I have on a 208vac 3-phase breaker?
The total loading on this panel is 6amps at 120vac L-N plus the 13.2 amps 208vac L-L. If I do the math:
6A @120v = 720VA (phase A)
13.2@208v = 2746VA (phase B and C)
25% motor = 687VA
Total panel VA = 4153VA
If I convert this 4153VA to 208VAC 3PH:
4153VA/208v/1.73 =11.54amps
This seems incorrect as it would indicate that a 15amp 3P 208v breaker would be sufficient based on the calculated FLA of the panel. However, looking at my loads I would need a 20amp breaker for my motor load which is higher than the main. In my calculation above do I need to account for 2X the VA of the single phase motor since the 13.2amp will be flowing out one leg and back on the other without a neutral to sum at the main breaker?
I am attempting to minimize the load/feed on this panel as it is almost 1000ft away from the source so every amp really matters with the voltage drop. That is why we are looking at a 3phase distribution but running the numbers they don't seem to be adding up.
I was also using the 3-phase load calculation for the voltage drop which I am now questioning also.
Thanks in advance for any help.