I have heard it two ways when it comes to considering the largest motor in a load calculation. Can someone help clarify this for me?
I am teaching a class on load calculations right now and I need to makes sure I have this right. The curriculum doesn't seem to spell it out clearly, (though, I admit, I'm probably missing something obvious)
The question (as an example):
Using the standard method, calculate the service load for a 2,200 square foot single family dwelling containing the following loads: range: 14kw at 240v, dryer 4.20kw at 240v, dishwasher 1.20kVA at 120v, waste disposer 1/4HP at 120v, water heater 4.2kw, a/c: 2 units 12A at 120V, electric heat 6kw at 240v, and attic fan 1.5HP at 120v.
the answer:
STEP 1: GENERAL LIGHTING
2200SQFT x 3 = 6600VA
+small appliance minimum: 3000VA
+laundry minimum: 1500VA
=11,100VA
FIRST 3000VA AT 100% = 3000VA
8100VA AT 35% = 2835VA
TOTAL GL: 5835VA
STEP 2: FASTENED IN PLACE APPLIANCES:
DISHWASHER: 1200VA
DISPOSAL: 696VA (PER 430.248)
ATTIC FAN: 2400VA (PER 430.248)
WATER HEATER: 4200VA
TOTAL: 8496 X 75% = 6372VA
TOTAL APPLIANCE LOAD: 6372VA
STEP 3: DRYER LOAD MINIMUM = 5000VA
STEP 4: COOKING EQUIPMENT: 14KW PER TABLE 220.55
COLUMN C = 8KW
+ 5% PER KW OVER 12 (2 X 5% = 10%)
8000 X 110% = 8800VA
STEP 5: NON-COINCIDENTAL LOADS: A/C AND HEAT
WE CAN OMIT A/C AND USE 6000VA AT 100%
STEP 6: LARGEST MOTOR. This is where the curriculum deviates from my interpretation. I would think you would need to take the 1.5 HP motor and consider the additional 25% for the calculation. OR if the A/C were the largest motor I would add 25% of that VA rating to the calculation.
I would think:
Largest motor: Attic Fan 2400VA
100% has alread been considered in the appliance load, but we need to add the 25%
2400VA x 25% = 600VA
I am teaching a class on load calculations right now and I need to makes sure I have this right. The curriculum doesn't seem to spell it out clearly, (though, I admit, I'm probably missing something obvious)
The question (as an example):
Using the standard method, calculate the service load for a 2,200 square foot single family dwelling containing the following loads: range: 14kw at 240v, dryer 4.20kw at 240v, dishwasher 1.20kVA at 120v, waste disposer 1/4HP at 120v, water heater 4.2kw, a/c: 2 units 12A at 120V, electric heat 6kw at 240v, and attic fan 1.5HP at 120v.
the answer:
STEP 1: GENERAL LIGHTING
2200SQFT x 3 = 6600VA
+small appliance minimum: 3000VA
+laundry minimum: 1500VA
=11,100VA
FIRST 3000VA AT 100% = 3000VA
8100VA AT 35% = 2835VA
TOTAL GL: 5835VA
STEP 2: FASTENED IN PLACE APPLIANCES:
DISHWASHER: 1200VA
DISPOSAL: 696VA (PER 430.248)
ATTIC FAN: 2400VA (PER 430.248)
WATER HEATER: 4200VA
TOTAL: 8496 X 75% = 6372VA
TOTAL APPLIANCE LOAD: 6372VA
STEP 3: DRYER LOAD MINIMUM = 5000VA
STEP 4: COOKING EQUIPMENT: 14KW PER TABLE 220.55
COLUMN C = 8KW
+ 5% PER KW OVER 12 (2 X 5% = 10%)
8000 X 110% = 8800VA
STEP 5: NON-COINCIDENTAL LOADS: A/C AND HEAT
WE CAN OMIT A/C AND USE 6000VA AT 100%
STEP 6: LARGEST MOTOR. This is where the curriculum deviates from my interpretation. I would think you would need to take the 1.5 HP motor and consider the additional 25% for the calculation. OR if the A/C were the largest motor I would add 25% of that VA rating to the calculation.
I would think:
Largest motor: Attic Fan 2400VA
100% has alread been considered in the appliance load, but we need to add the 25%
2400VA x 25% = 600VA