I posted this in response to another forum thread, but got no response.
The formula I used was
A^+B^+C^-(AB+BC+CA)=N CURRENT IN 3 PH
I?ve never calculated out the current on the Neutral in 3-ph before. I?ve always assumed if my circuits were close to being balanced and used for linear loads that I had no need to count the N as current carrying.
A B C N
10 10 10 0
10 10 0 10
6 15 9 63
10 10 2 64
16 16 0 256
16 16 2 196
16 16 14 4
Shut off a few switches, and the amps jump down on 1 phase and the N sky rockets.
Am I doing the math right??????????? I can?t be!!
What do harmonic loads do to the Neutral???
The formula I used was
A^+B^+C^-(AB+BC+CA)=N CURRENT IN 3 PH
I?ve never calculated out the current on the Neutral in 3-ph before. I?ve always assumed if my circuits were close to being balanced and used for linear loads that I had no need to count the N as current carrying.
A B C N
10 10 10 0
10 10 0 10
6 15 9 63
10 10 2 64
16 16 0 256
16 16 2 196
16 16 14 4
Shut off a few switches, and the amps jump down on 1 phase and the N sky rockets.
Am I doing the math right??????????? I can?t be!!
What do harmonic loads do to the Neutral???