First off, is this an NEC installation? Between your use of meters as a unit of measurement, and the fact that this is street lighting, I wonder if there is some other code that applies.
That being said, the method I use is the one outlined in the City of Los Angeles Electrical Code. The basic equation is: VD = Z * I * L, where Z is the impedance per unit length of your wire (Ohms), I is your current (Amps), and L is the length of your circuit. It is worth noting that the length of a single phase circuit is twice the distance between the source and the load, because you have to account for the length of both the supply and return conductors. Also, your current is not just the current required by your light; it's the current required by the light you're looking at, plus the current of all the other lights downstream from it on that same circuit.
Once you've calculated your voltage drop, you can convert it to percent voltage drop by dividing the voltage drop by the supply voltage and then multiplying by 100%.
Per City of LA requirements, I get my value of Z from NEC Chapter 9, Table 8 for conductors #2 AWG or smaller, and from NEC Chapter 9, Table 9 for conductors larger than #2 AWG. When using Table 8, I use the values for DC resistance of uncoated copper; if you're using copper conductors with coated strands or aluminum conductors, you would use the appropriate column from the table. When using Table 9, I use the values for Effective Z at 0.85 PF for uncoated copper wires. Again, if you're using aluminum, you need to use that column instead.
I've seen people use only the values from Table 8, others use only the values for Table 9, and still others use some other method altogether. The NEC doesn't say how you have to calculate voltage drop, it only suggests that you do so.
Looking back at my explanation, I'm realizing that voltage drop calcs can be more complicated than I normally think about. I guess that's what happens when you do them all the time. If you post some more information (supply voltage, wire size, number of lights, amps per light, etc.), we can probably give you a little more specific help.