3 phase heating element delta configuration

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!62

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Hello;
I have a 480vac three phase combination series parallel element (resistive load) totaling 2770 watts in a delta configured circuit. After a nodal analysis and KCL, my REQ ckt. is three elements in a delta configuration with two elements of 213 ohms and one element of 371 ohms with a total of approx.. 4 amps drawn. I know that only 480v is applied between any two lines at a time which is single phase or the √2; however, I used the two following equations to determine Line Phase Current:
Ln1 – Ln2 = 1079w and 213 Ω (due to seriesparallel elements)
Ln2 – Ln3 = 1079w and 213 Ω (due to seriesparallel elements)
Ln3 – Ln1 = 621wand 371Ω (due to series elements)

#1). ILine = 1.8A x √3,
#2). Ln1 = √A2 + C2 + (A x C),
Ln2 = √B2 + A2 + (B x A), and
Ln3 = √C2 + B2 + (C x B).

Can anyone confirm these equations and/or givean equation to complete the circuit.
As well, without using a pf to arrive at amps Idid use 2770w/480v x √3 = 3.33A total draw.



 
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