jrsparkdog
Member
- Location
- Buffalo, NY, USA
Hello,
I have a 120 V / 30 A, LED sign that i need to run power to. It is located 350 feet from the panel.
My calculations tell me that I need to run 1 AWG to that sign, for proper voltage drop.
Vd = (2 x K x D x I) / CM
Just to me that seems outrageous! Myself and fellow electricians I'ved worked with say the same thing. We believe that it should be more like 6 or 4 AWG. But my calculation says differently?
Am I doing something wrong with my calculation?
Any help is greatly appreciated and if I left anything out just ask.
I have a 120 V / 30 A, LED sign that i need to run power to. It is located 350 feet from the panel.
My calculations tell me that I need to run 1 AWG to that sign, for proper voltage drop.
Vd = (2 x K x D x I) / CM
Just to me that seems outrageous! Myself and fellow electricians I'ved worked with say the same thing. We believe that it should be more like 6 or 4 AWG. But my calculation says differently?
Am I doing something wrong with my calculation?
Any help is greatly appreciated and if I left anything out just ask.