Greg1707
Senior Member
- Location
- Alexandria, VA
- Occupation
- Business owner Electrical contractor
I saw this question in the EC Magazine:
Example Problem: What’s the maximum size overcurrent protection device for a 4,500W, 240V water heater?
Solution: Protection Size = 4,500W ÷ 240V = 18.75A × 150% = 28A
Answer: 28A doesn’t correspond to a standard ampere rating, so use 30A which is the next size up [Sec. 240.6(A)].
I was not familiar with this part of the code. I would have approached this question from the idea of what would be the minimum over current protection for a water heater. I thought the installation of a water heater would be: 18.75 amps x 125% = 23.4 amps and use a 30 amp breaker because that is what is available at the supply house!
Example Problem: What’s the maximum size overcurrent protection device for a 4,500W, 240V water heater?
Solution: Protection Size = 4,500W ÷ 240V = 18.75A × 150% = 28A
Answer: 28A doesn’t correspond to a standard ampere rating, so use 30A which is the next size up [Sec. 240.6(A)].
I was not familiar with this part of the code. I would have approached this question from the idea of what would be the minimum over current protection for a water heater. I thought the installation of a water heater would be: 18.75 amps x 125% = 23.4 amps and use a 30 amp breaker because that is what is available at the supply house!