Using 430.62-3 I can size a Feeder Circuit breaker smaller than what I can calculate in 215.3. For example. I have 2 motors branch circuits and 1 heater branch circuits. The FLA on the motors are 12 amps and 4 amps, and the FLA of the heater is 10amps.
Using 215.3 I get (12*1.25)+4+(10*1.25)= 31.5 so a 35A breaker
Using 430.63 I get (for a minimum) (12*1.25)+4+10= 29 so a 30A minimum breaker.
This is just an example, but this situation arrises when you use a time delay fuse that allows you to size the branch OCPD that allows you to size the largest motor at 125%. I know I use the actual breaker rating for 430.63, but in this case 12*1.25 is 15, which is what I use for the OCPD in this example.
So, can I use this smaller breaker or do I have to use the value from 214.3 first? In the above example, using 430.63 I would have a 30A breaker but a minimum circuit ampacity of 35A...so I would have a 30A breaker forced to protect 8AWG wire.
Using 215.3 I get (12*1.25)+4+(10*1.25)= 31.5 so a 35A breaker
Using 430.63 I get (for a minimum) (12*1.25)+4+10= 29 so a 30A minimum breaker.
This is just an example, but this situation arrises when you use a time delay fuse that allows you to size the branch OCPD that allows you to size the largest motor at 125%. I know I use the actual breaker rating for 430.63, but in this case 12*1.25 is 15, which is what I use for the OCPD in this example.
So, can I use this smaller breaker or do I have to use the value from 214.3 first? In the above example, using 430.63 I would have a 30A breaker but a minimum circuit ampacity of 35A...so I would have a 30A breaker forced to protect 8AWG wire.