brother
Senior Member
Im having a discussion with some fellow people about a 3 phase 480 v water heater. they say the specs 12.5 amps. 12,000 watt 480v . They were going to use #12 copper with 15 amp fuses.
I told them that water heaters branch circuit rating have to be calculated at 125% of the load, so at a minimum it would be 12.5 x 1.25=15.6 so a 20amp fuse would be needed if what they told me was correct. which seems odd for a 12,000 watt 480 water heater
I had more concerns when I finally saw the paper work , that says,
'Simultaneous wiring 4 wire 3 phase operation Full load current in amperes (terminals L3/Terminals L1 and L2) '21.7/12.5 element wattage 6000/6000
If I am understanding this correctly, these heating elements (480volt 2 hots feed) will be on at the SAME TIME and the total name plate? amps is 21.7. So it would be 12,000 watt divided by 480=25amps So calculated branch circuit rating wold be 25 X1.25= 31.25 amps So a 40amp branch circuit would be required if you did just the math, but if you use the 21.7X 1.25=27.125 amps so a 30amp branch circuit required. I would not go below 30amps regardless. So the fuses should be 30 at a minimum #10 copper. Ideally I would run a 40amp branch circuit with #8copper.
I told them after seeing the paper work that the minimum would be 30amps with #10 if they go off of the name plate of 21.7. That 12.5 amps is just for 1 heating element draw when you replace the heating elements.
Am I correct in this? they keep saying its only 12.5amps and they will do a 20amp circuit. I do not believe this right.
I told them that water heaters branch circuit rating have to be calculated at 125% of the load, so at a minimum it would be 12.5 x 1.25=15.6 so a 20amp fuse would be needed if what they told me was correct. which seems odd for a 12,000 watt 480 water heater
I had more concerns when I finally saw the paper work , that says,
'Simultaneous wiring 4 wire 3 phase operation Full load current in amperes (terminals L3/Terminals L1 and L2) '21.7/12.5 element wattage 6000/6000
If I am understanding this correctly, these heating elements (480volt 2 hots feed) will be on at the SAME TIME and the total name plate? amps is 21.7. So it would be 12,000 watt divided by 480=25amps So calculated branch circuit rating wold be 25 X1.25= 31.25 amps So a 40amp branch circuit would be required if you did just the math, but if you use the 21.7X 1.25=27.125 amps so a 30amp branch circuit required. I would not go below 30amps regardless. So the fuses should be 30 at a minimum #10 copper. Ideally I would run a 40amp branch circuit with #8copper.
I told them after seeing the paper work that the minimum would be 30amps with #10 if they go off of the name plate of 21.7. That 12.5 amps is just for 1 heating element draw when you replace the heating elements.
Am I correct in this? they keep saying its only 12.5amps and they will do a 20amp circuit. I do not believe this right.
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