120622-0807 EDT
cizzle21p:
Current transformers are a current source, not a voltage source, over some reasonable range of output voltage. Thus, a change of load resistance on the current transformer makes little change in the current reading.
A 50:5 current transformer will have 10 turns on the secondary (5 amp side). The primary is 1 turn of the single wire thru the current transformer once. If you looped that input wire back thru the current transformer a second time, then it becomes a 25:5 transformer.
It is intended that a low impedance current meter be the load on the secondary of the current transformer. These meters might be in the range of 50 to 250 millivolts full scale.
You would use a 5 A meter movement on a 50:5 current transformer, but the scale would be calibrated 0 to 50. If you used a meter not matched to the current transformer and it was a 0 to 5 A meter and the scale read 0 to 5 A, then you would need to multiply the meter face reading by 10 to get your circuit current measurement.
Suppose the ammeter is 50 millivolts at 5 A, then its impedance is about 0.05/5 = 0.01 ohms.
Now suppose the burden rating of the current transformer is 10 VA. then the maximum load impedance you should place on the current transformer is 10/5
2 = 1/2.5 = 0.4 ohms to remain within the accuracy rating. Copper #14 wire is about 2.5 ohms per 1000 ft. To stay within 0.39 ohms the total wire loop length is 1000*0.39/2.5 = 156 ft. Thus the meter could be up to 75 ft from the current transformer with #14 copper wire.
Check my math for any mistakes.
See
http://electricalnotes.wordpress.com/2011/04/16/current-transformer/
.