120825-1314 EDT
Wild ball park figure.
Assume the end load is 60 HP 3 phase induction motor. More information is needed.
Assume 1KVA per HP or 60 KVA. This should take care of the motor inefficiency. Maybe not the power factor effect.
Assume the rotary phase converter has an efficiency of 75%. Then input KVA is about 60/0.75 = 80 . Not all the energy passes thru the rotary converter. Something under 33% goes directly to the load motor. This would be 33% but there are losses in the rotary converter that is supplying energy to the other two phases.
Thus, input single phase current from the line is about 80,000/230 = 350 A, or maybe more.
If the load could be a big single phase capacitor run motor, then the whole system would be more efficient and a better power factor. The line current might be about 260 A.
Alternatively a smaller DC motor might do what is needed and not require high inrush energy for start-up with the correct control.
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